Hi guys, does anyone know how to do the following? I want to set up an SNMPV3 user on my 3PAR but I want to be able to specify separate AUTH and PRIV passwords. Most devices allow you specify this but on the 3PAR it doesnt seem to. (I'm running 3.2.1.292 aka MU3). Create a user createuser myuser all browse Password for user myuser: Retype password for user myuser: User created 2. Create SNMP user createsnmpuser myuser Please enter the password below.
Some information on what is supported under SNMP, and there is also a mib file located on. 3Par Mib Download. Contents 3 Table of Contents Part 1 Introduction 5 1 About MIB Files 6 2 SNMP—The Simple Network Management Protocol 8 3 Supported MIB. Additionally, disk array components are often. Modern hard disk drives come with 8 to 256 MiB of such. File servers are commonly found in schools.
The password will be used to generate both authentication and privacy secret keys for use in SNMPv3. Password for user myuser: Retype password for user myuser: SNMP user successfully set. Add some destinations addsnmpmgr -snmpuser myuser -version 3 So there does not seem to be any way to specify a separate private key.
I see there's a command setsnmppw but I am guessing this is for SNMP V1.(believe it just changes the default PUBLIC auth for SNMPV1). Anyways, hoping someone maybe has done this already and can offer some advice.
Hopefully this information won’t be redundant but sometimes the propagation of sizing a storage solution should go beyond the calculation given by a tool. When calculating the space for CPGs and VVs in 3PAR the measurement the unit used is TiB (Tebibyte) / GiB (Gibibyte) / MiB(Mebibyte) where:.
Each TiB = 1.76 TB. Each GiB = 1.073741824 GB. Each MiB = 1.048576 MB. You can use this website for conversion, till now I presume this is know if you have a keen eye on noticing the measurement unit. On the other hand please take into consideration that the partition on Windows for example when initialized even though for example it’s a 16TiB (17.55TB) the usable disk space will be 15.9TB, why?
After doing some research I found out that to the hard disk manufacturers, one KB is 1000 bytes, one MB is 1000 KB, and one GB is 1000 MB. So if a hard disk is advertised as 1TB, it contains 1000. (1000.
1000. 1000) = 1000,000,000,000 bytes of space. The hard disk manufacturer thus advertises the disk as a 1TB hard disk so to get the exact number of available space for Windows we have to follow the following calculation because on the Windows OS a 1TB is 1024GB, as such we have to: 1000,000,000,000 / (1024. 1024.
1024) = 931GB usable disk space. Hopefully this would be informative to someone.